/sci/ - Science & Math » Thread #7621485

[13 / 2 / ?]

114KiB, 386x194, 142570a0b6b29a47f6cbb08c85f28fe9.png

View Same Google ImgOps iqdb SauceNAO

Anonymous Wed 28 Oct 2015 13:59:34 No.7621485 View Reply Report Delete

Quoted By: >>7621488 >>7621602 >>7622885 >>7623340

can anyone solve this for me?

Anonymous

Anonymous Wed 28 Oct 2015 14:01:03 No.7621488 Report Delete

Quoted By: >>7621497

>>7621485
I can.

Anonymous

Anonymous Wed 28 Oct 2015 14:02:29 No.7621490 Report Delete

Quoted By:

I can solve it, but it's probably better that you do your own homework anon.

Anonymous

Anonymous Wed 28 Oct 2015 14:03:20 No.7621492 Report Delete

Quoted By:

please guys, i have no idea how to do it :( Maybe you can even explain how it works

Anonymous

Anonymous Wed 28 Oct 2015 14:04:35 No.7621497 Report Delete

Quoted By: >>7621608

>>7621488
Okay I was just going to leave out at that, but it's not in my nature. It's simpler to do if you write the radicals as fractional powers so $\sqrt{a^3} = \left( a^3 \right)^{1/2}$ then use the laws of indices to simplify.

Anonymous

Anonymous Wed 28 Oct 2015 14:50:30 No.7621602 Report Delete

Quoted By:

>>7621485
((a^2*(a^2)^(1/3))^(1/4))^(1/2)
(a^2*a^(2/3))^(1/8)
(a^(8/3))^(1/8)
a^(1/3)
cube root of a

Anonymous

Anonymous Wed 28 Oct 2015 14:52:36 No.7621608 Report Delete

Quoted By: >>7621622

>>7621497
Exactly what this guy said. Writing radicals in its exponential form is an easy way to approach these problems.

Use the following fact:
$\sqrt[n]{a} = a^{1/n}$

So we have that:
$\sqrt[4]{a} = a^{1/4}$
$\sqrt[3]{a} = a^{1/3}$
$\sqrt{a} = a^{1/2}$

So starting with the original problem:
$\sqrt{\sqrt[4]{\sqrt{a^2 \cdot \sqrt[3]{a^2}}}}$

We can change it to:
$((a^2 \cdot (a^{2})^{1/3})^{1/4})^{1/2}$

Now, work from the inside out, using the rules for exponents.

Anonymous

Anonymous Wed 28 Oct 2015 14:56:04 No.7621621 Report Delete

Quoted By:

this is easy as shit

=((a^2 * a^(2/3))^(1/4))^(1/2);
=((a ^ (2 + 2/3))^1/4)^(1/2);
=((a^(8/3))^1/4)^(1/2);
=(a^8/12)^(1/2);
=(a^2/3)^(1/2);
=a^(2/6);
=a^(1/3);

Anonymous

Anonymous Wed 28 Oct 2015 14:56:05 No.7621622 Report Delete

Quoted By:

>>7621608
I missed a root:

$(((a^2 \cdot (a^{2})^{1/3})^{1/2})^{1/4})^{1/2}$

Anonymous

Anonymous Thu 29 Oct 2015 00:58:30 No.7622885 Report Delete

Quoted By:

>>7621485
split that shit into parts:

a^(2/3)*a^2=a^(8/3)
a^(8/3)^(1/4)=a^(2/3)
a^(2/3)^(1/3)=a^(1/3)

Anonymous

View Same Google ImgOps iqdb SauceNAO Screenshot_2015-10-29-00-51-52.png, 192KiB, 1440x2560

Anonymous Thu 29 Oct 2015 03:52:35 No.7623340 Report Delete

Quoted By: >>7623347

>>7621485

Anonymous

Anonymous Thu 29 Oct 2015 03:55:06 No.7623347 Report Delete

Quoted By: >>7623363

>>7623340
Lg g3?

Anonymous

Anonymous Thu 29 Oct 2015 04:03:33 No.7623363 Report Delete

Quoted By:

>>7623347
Yup

Subject

Name

E-mail

Password

Capcode	All Only User Posts Only Verified Posts Only Moderator Posts Only Manager Posts Only Admin Posts Only Developer Posts Only Founder Posts
Show Posts	All Only With Images Only Without Images Only Spoiler Images Only Non-Spoiler Images
Deleted Posts	All Only Deleted Posts Only Non-Deleted Posts
Ghost Posts	All Only Ghost Posts Only Non-Ghost Posts
Post Type	All Only Sticky Threads Only Opening Posts Only Reply Posts
Results	All Grouped By Threads
Order	Latest Posts First Oldest Posts First

On these boards

Your latest searches