/sci/ - Science & Math » Thread #7624204

[74 / 7 / ?]

70KiB, 581x656, 1446145423162.jpg

View Same Google ImgOps iqdb SauceNAO

Anonymous Thu 29 Oct 2015 15:28:31 No.7624204 View Reply Report Delete

So.../sci/?
How do you solve this?

Anonymous

Anonymous Thu 29 Oct 2015 15:29:35 No.7624205 Report Delete

Quoted By: >>7624209 >>7624213 >>7626384

6 + 11 + 13 = 30

Anonymous

Anonymous Thu 29 Oct 2015 15:30:56 No.7624208 Report Delete

Quoted By: >>7624213 >>7624237 >>7625459 >>7626421

>>7624204
>all odds
>sum 3 odds will not be even
at this point you know it's either unsolvable, or you can use fractions

Anonymous

Anonymous Thu 29 Oct 2015 15:31:03 No.7624209 Report Delete

Quoted By: >>7624210 >>7626201

>>7624205
>6

Anonymous

Anonymous Thu 29 Oct 2015 15:31:32 No.7624210 Report Delete

Quoted By: >>7626201 >>7626382

>>7624209
Rotate the 9 to get 6.

Anonymous

Anonymous Thu 29 Oct 2015 15:32:33 No.7624213 Report Delete

Quoted By:

>>7624205
>6

>>7624208
this. the only correct answer is to leave that shit-stain country and go to europe.

Anonymous

Anonymous Thu 29 Oct 2015 15:35:01 No.7624218 Report Delete

Quoted By: >>7624219

>>7624204
+15+15

Anonymous

Anonymous Thu 29 Oct 2015 15:35:31 No.7624219 Report Delete

Quoted By:

>>7624218

Fuck off

Anonymous

Anonymous Thu 29 Oct 2015 15:49:20 No.7624237 Report Delete

Quoted By:

>>7624208
This is the conclusion I arrived at after about a minute of reading the problem. It's probably one of those { 1=3; 2=3; 3=5; 4=4; 5=? } Only true geniuses will be able to solve this!

Anonymous

Anonymous Thu 29 Oct 2015 15:51:49 No.7624239 Report Delete

Quoted By:

30 mod 9 = 3

1+1+1 = 3

checkmate theists

Anonymous

Anonymous Thu 29 Oct 2015 16:12:19 No.7624271 Report Delete

Quoted By: >>7624302

>>7624204
The question is asking
>Can you solve this?
The answer is no, the sum of three odds can never equal an even number.

Anonymous

Anonymous Thu 29 Oct 2015 16:31:03 No.7624302 Report Delete

Quoted By: >>7624352 >>7624353 >>7624356 >>7624371

>>7624271

But it said someone solved it, so given that, I would suggest not thinking in base 10.
There are 5 symbols showing and a zero 0,1,3,5,7,9

so, in base 5 with alphabet 00,01,03,05,09,10,11...etc
The answer would be
9 + 9 + 15 = 30

Anonymous

Anonymous Thu 29 Oct 2015 16:54:09 No.7624340 Report Delete

Quoted By: >>7624371

(11-1)+(13-3)+(15-5)=30
Keep studying kiddos

Anonymous

Anonymous Thu 29 Oct 2015 16:57:15 No.7624352 Report Delete

Quoted By: >>7624540

>>7624302
Or maybe the answer is to prove that it is impossible.

a + b + c = 30
where a,b,c are in the set of positive odd numbers smaller than 17.

we get
a = 30 - b - c whicn can be written as
a = 30 - (b+c)

But we have a contradiction. 30 is an even number, substracted by two odd numbers so
a = 30 - n where n is an even number
but an even number minus an even number is an even number.

That means that a must be an even number.
But no even numbers exist in the set and that is our contradiction.

QED?

Anonymous

Anonymous Thu 29 Oct 2015 16:57:26 No.7624353 Report Delete

Quoted By:

>>7624302
>base 5
>9

nigger are you se

Anonymous

Anonymous Thu 29 Oct 2015 17:00:16 No.7624356 Report Delete

Quoted By:

>>7624302
> But it said someone solved it
They lied.

Anonymous

Anonymous Thu 29 Oct 2015 17:02:20 No.7624361 Report Delete

Quoted By: >>7624362

>>7624204
15 + 15 + __ = 30

lol

Anonymous

Anonymous Thu 29 Oct 2015 17:04:00 No.7624362 Report Delete

Quoted By: >>7624366

>>7624361
you only filled 2 of them

Anonymous

Anonymous Thu 29 Oct 2015 17:05:40 No.7624366 Report Delete

Quoted By: >>7624367

>>7624362
And?

Anonymous

Anonymous Thu 29 Oct 2015 17:06:18 No.7624367 Report Delete

Quoted By: >>7624369

>>7624366
it means there is one more box to fill...

Anonymous

Anonymous Thu 29 Oct 2015 17:07:07 No.7624369 Report Delete

Quoted By: >>7624372

>>7624367
Yeah, so?

Anonymous

View Same Google ImgOps iqdb SauceNAO puzzle.jpg, 70KiB, 581x656

Anonymous Thu 29 Oct 2015 17:08:13 No.7624371 Report Delete

Quoted By:

>>7624302
On the right track, but redefining the symbol set for base 5 is stretching the rules a bit... I could say 5 + 17 + 1 are three symbols that equal the symbol 30 in base 17.3.
>>7624340
"you can also repeat the numbers" - doesn't say you can repeat the brackets, nice try though.
pic related is the solution I posted last time this was spammed on /sci/... seems simplest though obviously there are numerous similar ones.

Anonymous

Anonymous Thu 29 Oct 2015 17:08:25 No.7624372 Report Delete

Quoted By: >>7624379

>>7624369
which you didn't, which means it's not a valid solution

Anonymous

Anonymous Thu 29 Oct 2015 17:08:46 No.7624375 Report Delete

Quoted By:

>>7624204
(5+5)+(5+5)+(5+5)

Anonymous

Anonymous Thu 29 Oct 2015 17:10:49 No.7624379 Report Delete

Quoted By: >>7624387 >>7624389

>>7624372
>15 + 15 + 0 =/= 30
I would sue them and win.

Anonymous

Anonymous Thu 29 Oct 2015 17:13:46 No.7624387 Report Delete

Quoted By:

>>7624379
u suk dik :o

Anonymous

Anonymous Thu 29 Oct 2015 17:14:07 No.7624389 Report Delete

Quoted By:

>>7624379
blank space =/= 0

Anonymous

View Same Google ImgOps iqdb SauceNAO 873141289m1.gif, 263KiB, 400x452

Anonymous Thu 29 Oct 2015 17:34:35 No.7624426 Report Delete

Quoted By:

()+15+15=30

Anonymous

Anonymous Thu 29 Oct 2015 17:52:41 No.7624464 Report Delete

Quoted By: >>7624540 >>7625464

>>7624204
Base 5
11 + 11 + 3 = 30
in base 10
6 + 6 + 3 = 15

Anonymous

Anonymous Thu 29 Oct 2015 18:29:30 No.7624540 Report Delete

Quoted By:

>>7624352
An odd number can be written as 2k + 1 where k is an integer.

The sum of three arbitrary odd numbers, 2m + 1, 2n + 1, and 2j + 1, will be

(2m + 1) + (2n + 1) + (2j + 1)

= 2m + 2n + 2j + 3

= 2(m + n + j + 1) + 1

(m + n + j + 1) is an integer because the set of integers is closed under addition.

Therefore, the sum of any 3 odd integers is odd.

But yeah if you redefine the system as base-(some odd number), it will work because that turns some of the listed numbers into even numbers. As in >>7624464

Anonymous

Anonymous Thu 29 Oct 2015 18:49:34 No.7624585 Report Delete

Quoted By:

>>7624204
1,3 + 5,7 + 13 = 30

Get rekt

Anonymous

Anonymous Thu 29 Oct 2015 18:58:34 No.7624611 Report Delete

Quoted By: >>7625561

>>7624204
(1)+15+15

It's why there's brackets in there.

Anonymous

View Same Google ImgOps iqdb SauceNAO Common-Core-Logo[1].png, 17KiB, 410x426

Anonymous Thu 29 Oct 2015 19:01:40 No.7624615 Report Delete

Quoted By: >>7624627

1 + 3 + 5 = 30

: ^ )

Anonymous

Anonymous Thu 29 Oct 2015 19:03:42 No.7624620 Report Delete

Quoted By: >>7624644

> Can you solve this?
"No."

Anonymous

Anonymous Thu 29 Oct 2015 19:06:20 No.7624627 Report Delete

Quoted By:

>>7624615
No on loves you. You will die alone.

Anonymous

View Same Google ImgOps iqdb SauceNAO 028334659.jpg, 37KiB, 464x290

Anonymous Thu 29 Oct 2015 19:14:03 No.7624644 Report Delete

Quoted By:

>>7624620

Anonymous

View Same Google ImgOps iqdb SauceNAO 1445683865390.jpg, 52KiB, 581x656

Anonymous Thu 29 Oct 2015 19:14:47 No.7624647 Report Delete

Quoted By: >>7626235

Anonymous

Anonymous Thu 29 Oct 2015 19:40:17 No.7624710 Report Delete

Quoted By:

>>7624204

"The parameters of this problem are ill defined"

Anonymous

Anonymous Fri 30 Oct 2015 00:16:56 No.7625385 Report Delete

Quoted By: >>7626463

>>7624204
math phd here

11+7+13

this digits not decimal, its 11
/thread

Anonymous

Anonymous Fri 30 Oct 2015 00:24:34 No.7625393 Report Delete

Quoted By:

>>7624204
>Three odd numbers to add to an even number
Not possible.

Anonymous

Anonymous Fri 30 Oct 2015 01:10:56 No.7625459 Report Delete

Quoted By:

>>7624208
You can't even use fractions. An odd times an odd is still odd, so an odd divided by an odd is also odd provided that the result is a whole number.

Anonymous

Anonymous Fri 30 Oct 2015 01:15:42 No.7625464 Report Delete

Quoted By:

>>7624464
This.

Anonymous

Anonymous Fri 30 Oct 2015 01:22:26 No.7625470 Report Delete

Quoted By:

>>7624204
Not even converting the values to hexadecimal can you solve this problem.

Anonymous

Anonymous Fri 30 Oct 2015 01:27:10 No.7625473 Report Delete

Quoted By:

Cannot be solved, see: parity

Anonymous

Anonymous Fri 30 Oct 2015 02:20:19 No.7625526 Report Delete

Quoted By:

>>7624204

I would like to know the solution that Gaurav Agarwal used.

Tried googling it with the information provided in OP's pic, but didnt find any relevant results.

I am just hoping its not some smarty pants answer that uses a solution outside the bounds of what the question appears to ask to us plebs.

Anonymous

Anonymous Fri 30 Oct 2015 02:25:33 No.7625536 Report Delete

Quoted By: >>7625547 >>7625558 >>7626466 >>7626478

Guarav Agarwal (the guy who got it correct) posted his notes for the answers he gave. In the comments of that post someone asked him what answer he gave for this problem. He replied "15+15+=30" (the original question had three boxes, not five). The problem was to "fill the boxes"; but it didn`t say to fill ALL the boxes.... https://thesupermanreturns.wordpress.com/2013/12/12/upsc-mains-2013-solved-general-studies-paper-1/

Anonymous

Anonymous Fri 30 Oct 2015 02:43:17 No.7625547 Report Delete

Quoted By:

>>7625536
That's not even a syntactically well-formed equation. There must have been a hint during the lectures that this would be acceptable.

Anonymous

Anonymous Fri 30 Oct 2015 03:05:36 No.7625558 Report Delete

Quoted By:

>>7625536
There weren't any explicit rules in the question either against killing the rest of the participants, thus forcing your win.

Anonymous

Anonymous Fri 30 Oct 2015 03:11:36 No.7625561 Report Delete

Quoted By:

>>7624611
() = 0

()+15+15= 30

Anonymous

Anonymous Fri 30 Oct 2015 10:09:12 No.7625892 Report Delete

Quoted By:

>>7624204
>You will be glad to note that only Gaurav Agarwal (IAS Topper) could solve it.

I really am glad for him

Anonymous

Anonymous Fri 30 Oct 2015 11:10:48 No.7625974 Report Delete

Quoted By:

Makes no sense
We can only use the addition and the N set, thus using the group (N, +), which by definition contains only 1 neutral element, 0. Defining () as being a neutral element for addition, that would mean that there's a problem with our group.
Therefore () cannot be used as an element of (N, +)

Anonymous

Anonymous Fri 30 Oct 2015 13:30:53 No.7626201 Report Delete

Quoted By:

>>7624210
>>7624209
it says numbers not symbols

Anonymous

Anonymous Fri 30 Oct 2015 13:47:30 No.7626235 Report Delete

Quoted By:

>>7624647
kek

Anonymous

Anonymous Fri 30 Oct 2015 13:54:34 No.7626252 Report Delete

Quoted By: >>7626256

9.99... +9.99... +9.99... = 30

Anonymous

Anonymous Fri 30 Oct 2015 13:55:14 No.7626256 Report Delete

Quoted By: >>7626261

>>7626252
9.99... isn't one of the choices. try again

Anonymous

Anonymous Fri 30 Oct 2015 13:55:55 No.7626261 Report Delete

Quoted By: >>7626265

>>7626256
>you can repeat the numbers

Anonymous

Anonymous Fri 30 Oct 2015 13:56:54 No.7626265 Report Delete

Quoted By: >>7626294

>>7626261
You can repeat the numbers that are provided. 9.99... isn't provided.

Anonymous

Anonymous Fri 30 Oct 2015 14:03:22 No.7626285 Report Delete

Quoted By: >>7626434

>>7624204
(15)++

It's simple Computer Science guys.

Anonymous

Anonymous Fri 30 Oct 2015 14:07:12 No.7626291 Report Delete

Quoted By:

>>7624204
Anyone with a pulse can prove that it's not solvable.
Take three uneven numbers. They are (2x+1), (2y+1) and (2z+1), with x,y,z WHOLE NUMBERS. The sum of these three uneven numbers should equal 30, which means (x+y+z) = 13.5
But x, y and z are even, and we have arrived at a contradiction. Three whole numbers can not make 13.5

Anonymous

Anonymous Fri 30 Oct 2015 14:08:23 No.7626294 Report Delete

Quoted By:

>>7626265
He means you repeat the 9's

Anonymous

Anonymous Fri 30 Oct 2015 14:43:02 No.7626361 Report Delete

Quoted By:

>>7624204
(15x9) + (-15x5) + (-15-15) = 30

Anonymous

Anonymous Fri 30 Oct 2015 14:51:06 No.7626376 Report Delete

Quoted By:

>using paranthesis to describe a set

Why would anyone care about the question past this point?

Anonymous

Anonymous Fri 30 Oct 2015 14:56:04 No.7626382 Report Delete

Quoted By:

>>7624210
This is the only way I could see it logically.

Anonymous

Anonymous Fri 30 Oct 2015 14:57:55 No.7626384 Report Delete

Quoted By:

>>7624205
[1+5] + [11] + [13] = 30

No rules were specified.

Anonymous

Anonymous Fri 30 Oct 2015 15:05:36 No.7626404 Report Delete

Quoted By:

Wait, it doesn't say to fill all boxes [15] + [15] = 30.

Anonymous

Anonymous Fri 30 Oct 2015 15:10:41 No.7626421 Report Delete

Quoted By:

>>7624204
If numbers and fractions are permitted, there are multiple solutions. Given we are only allowed to use certain permutations of the numbers provided. Here's one solution:

15 + 9 .1 + 5 .9 = 30

Otherwise, if we're allowed to use them in integers as operands of addition only, then vide by >>7624208

Anonymous

Anonymous Fri 30 Oct 2015 15:15:37 No.7626433 Report Delete

Quoted By:

>>7624204
11+11+3=30 in base 5

Anonymous

Anonymous Fri 30 Oct 2015 15:15:53 No.7626434 Report Delete

Quoted By:

>>7626285
Kek

Anonymous

Anonymous Fri 30 Oct 2015 15:32:38 No.7626463 Report Delete

Quoted By:

>>7625385
31

Anonymous

Anonymous Fri 30 Oct 2015 15:34:35 No.7626466 Report Delete

Quoted By:

>>7625536
Actually +15+15 would be because its positive 15 plus 15

Really, even his answer was incorrect

Anonymous

View Same Google ImgOps iqdb SauceNAO 1404136696395.png, 576KiB, 738x687

Anonymous Fri 30 Oct 2015 15:40:07 No.7626478 Report Delete

Quoted By:

>>7625536
>15+15+
>curryniggers in charge of syntax

Anonymous

Anonymous Fri 30 Oct 2015 15:49:32 No.7626496 Report Delete

Quoted By:

>>7624204
11+13+(upside down 9)=30

Anonymous

Anonymous Fri 30 Oct 2015 17:33:38 No.7626676 Report Delete

Quoted By:

>>7624204
13.5 + 13.5 + 3

Anonymous

Anonymous Fri 30 Oct 2015 17:41:27 No.7626689 Report Delete

Quoted By:

Well, this Mongolian Glyph Study board proved that different solutions exist to answer this problem, and that only one curryboy was able to solve it. Outsourcing is bringing demise to the west.

Subject

Name

E-mail

Password

Capcode	All Only User Posts Only Verified Posts Only Moderator Posts Only Manager Posts Only Admin Posts Only Developer Posts Only Founder Posts
Show Posts	All Only With Images Only Without Images Only Spoiler Images Only Non-Spoiler Images
Deleted Posts	All Only Deleted Posts Only Non-Deleted Posts
Ghost Posts	All Only Ghost Posts Only Non-Ghost Posts
Post Type	All Only Sticky Threads Only Opening Posts Only Reply Posts
Results	All Grouped By Threads
Order	Latest Posts First Oldest Posts First

On these boards

Your latest searches